.5x^2-8800=0

Solution for .5x^2-8800=0 equation:

.5x^2-8800=0

a = .5; b = 0; c = -8800;
Δ = b2-4ac
Δ = 02-4·.5·(-8800)
Δ = 17600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{17600}=\sqrt{1600*11}=\sqrt{1600}*\sqrt{11}=40\sqrt{11}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{11}}{2*.5}=\frac{0-40\sqrt{11}}{1}
=-\frac{40\sqrt{11}}{1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{11}}{2*.5}=\frac{0+40\sqrt{11}}{1}
=\frac{40\sqrt{11}}{1}
$